Quantity Surveying: 2023

Plastering work- Manpower calculation

1.Internal Wall plastering:

Manpower required per day for Internal wall plastering (8hrs/day):

Internal wall plastering- 10 sqm

1 manson

1 male mazdoor

1 female mazdoor

That means 1manson, 1 male mazdoor,1 female mazdoor complete the Internal wall plastering 10 sqm in 8hrs.

Example: Calculate the manpower required for to complete the 100 sqm Internal wall plastering in 2 days?

Solution: Qty=100sqm

Duration= 2 days

Per day productivity = 100/2 = 50 sqm

No of mason,male mazdoor,female mazdoor= 50/10=5 nos

No of mason=5(per day)

No of male mazdoor=5(per day)

No. of female mazdoor =5( per day)

To complete the Internal wall plastering work= 10 no of manson

=10 no of Male mazdoor

=10 no of female mazdoor

2.External and Ceiling wall plastering:

Manpower required per day for External wall and ceiling plastering (8hrs/day):

Internal wall plastering- 8 sqm

1 manson

1 male mazdoor

1 female mazdoor

That means 1manson, 1 male mazdoor,1 female mazdoor complete the External wall and ceiling plastering 8 sqm in 8hrs.

Example: Calculate the manpower required for to complete the 100 sqm External wall plastering and ceiling plastering in 2 days?

Solution: Qty=100sqm

Duration= 2 days

Per day productivity = 100/2 = 50 sqm

No of mason,male mazdoor,female mazdoor= 50/8=4 nos

No of mason=4(per day)

No of male mazdoor=4(per day)

No. of female mazdoor =4( per day)

To complete the Internal wall plastering work= 8 no of manson

=8 no of Male mazdoor

=8 no of female mazdoor

Labour Productivity- Block work and Brick work (Manpower calculation)

1.AAC BLOCK WORK (600X200X200)mm or (24X8X8) inch

Manpower required per day for block work (8hrs/day):

AAC BLOCK WORK -8inch- 10 sqm

1 manson

1 male mazdoor

1 female mazdoor

That means 1manson, 1 male mazdoor,1 female mazdoor complete the blockwork 10 sqm in 8hrs.

Example: Calculate the manpower required for to complete the 100 sqm block work (AAC BLOCK WORK (600X200X200)mm in 2 days?

Solution: Qty=100sqm

Duration= 2 days

Per day productivity = 100/2 = 50 sqm

No of mason,male mazdoor,female mazdoor= 50/10=5 nos

No of mason=5(per day)

No of male mazdoor=5(per day)

No. of female mazdoor =5( per day)

To complete the 100 sqm block work= 10 no of manson

=10 no of Male mazdoor

=10 no of female mazdoor

2.AAC BLOCK WORK (600X200X100)mm or (24X8X4) inch and (600X200X150)mm or (24X8X6) inch

Manpower required per day for block work (8hrs/day):

AAC BLOCK WORK -6 and 4inch- 8

1 male mazdoor

1 female mazdoor

That means 1manson, 1 male mazdoor,1 female mazdoor complete the blockwork 8 sqm in 8hrs.

Example: Calculate the manpower required for to complete the 50 sqm block work (AAC BLOCK WORK (600X200X150&100)mm in 2 days?

Solution: Qty=50sqm

Duration= 2 days

Per day productivity = 50/2 = 25 sqm

No of mason,male mazdoor,female mazdoor= 25/8=3.2=3.2 nos

No of mason=3.2(per day)

No of male mazdoor=3.2(per day)

No. of female mazdoor =3.2( per day)

To complete the 50 sqm block work= 6.4=7 no of manson

=6.4=7 no of Male mazdoor

=6.4=7 no of female mazdoor

3.BRICK WORK (190X90X90)mm

Manpower required per day for 9 inch brick work (8hrs/day):

Brick work-9inch- 1.25cum

1 manson

1 male mazdoor

1 female mazdoor

That means 1manson, 1 male mazdoor,1 female mazdoor complete the brickwork 9inch 1.25cum in 8hrs.

Example: Calculate the manpower required for to complete the 20 cum brick work 9inch in 2 days?

Solution: Qty=20cum

Duration= 2 days

Per day productivity = 20/2 = 10 cum

No of mason,male mazdoor,female mazdoor= 10/1.25=8 nos

No of mason=8(per day)

No of male mazdoor=8(per day)

No. of female mazdoor =8( per day)

To complete the 20cum brick work= 16 no of manson

=16 no of Male mazdoor

=16 no of female mazdoor

4.BRICK WORK (190X90X90)mm

Manpower required per day for 4.5 inch brick work (8hrs/day):

Brick work-4.5inch- 5 sqm

1 manson

1 male mazdoor

1 female mazdoor

That means 1manson, 1 male mazdoor,1 female mazdoor complete the brickwork 9inch 5sqm in 8hrs.

Example: Calculate the manpower required for to complete the 150sqm brick work 4.5inch in 2 days?

Solution: Qty=150 sqm

Duration= 2 days

Per day productivity = 150/2 = 75 sqm

No of mason,male mazdoor,female mazdoor= 75/5=15 nos

No of mason=15(per day)

No of male mazdoor=15(per day)

No. of female mazdoor =15( per day)

To complete the 150 sqm brick work= 30 no of manson

=30 no of Male mazdoor

=30 no of female mazdoor

Estimates/Quantity Surveying

What is Estimates?

The construction project's estimated cost was delivered in advance.

The estimation is made:

If there is enough money, to allocate a certain sum to the project, or to adjust the project's specifications to fit the available funds.

Types of projects:

Building

Roads

Airports

Bridges

Culverts

Rate Analysis of cement mortar

Rate Analysis of cement mortar:

Data required for rate analysis for cement mortar:

A. Material cost

B .Labour cost

A. Material required for cement mortar

1.Cement bag=350/-(APPROX)

2. Sand=1539/-(APPROX)

B.Labour required for 1CUM of cement mortar

1. Mazdoor= .75 per cum

2.Bhisti=.07 per cum

Mazdoor rate=500/- per day

Bhisti rate=400/- per day

1.Calculate cement content and sand content for 1 cum of cement mortar, CM:1:6

Dry Volume of cement mortar = (33%*1)+1

=.33+1= 1.33 cum

1.Cement content =1.33*((1/(1+6))

=1.33*.143

=.19 cum

Weight of cement= density of cement* volume

=1440 kg/m3* .19m3

=273.6 kg

1 cement bag = 50 kg

No. of cement bags required for cum mortar =273.6/50=5.5 bags=6 bags

2. Sand Content= 1.33*((6/(1+6))

=1.14 cum

Weight of sand= 1700 kg/m3*1.14 m3

= 1938 kg

= Cement content in cum x 6 times (CM Ratio 1:6)

=.19*6

=1.14cum

Rate Analysis

1. Material cost

a) Cement Bag= 6* 350/-

=2100

b) Sand= 1.14*1539/-

=1755/-

Total Material cost= 2100+1755

=3855/-

2. Labour Cost

a) Mazdoor=.75*500

=375

b) Bhisti= .007*400

=28/-

Total Labour cost=403/-

Material cost+Labour cost=3855+403=4258/-

Add Water charges on Total amt= 4258*(1.5)%

=64

Add 10% Contractors profit=4258*10%

=425/-

Total Rate per cum of cement mortar=4258+425+64

=4747/-

What is Fine Aggregate?

Fine Aggregate: The crucial component in the production of concrete, fine aggregate is made up of particles that can pass through a 4.75mm IS Sieve.

ex: Sand, River sand, crushed stone, M sand

Density of steel, Density of RCC, Density of PCC, Density of Fine aggregate, Density of coarese aggregate

Density of Construction materials:

As a Civil Engineer should have knowledge on density of construction materials and this question is commonly asking question in interview.

As per IS code

RCC=2500KG/M3

PCC=2400KG/M3

STEEL=7850KG/M3

CEMENT=1440KG/M3

BRICKS=1600 TO 1920 KG/M3

FINE AGGREGATE=1500 TO 1700 KG/M3

COARSE AGGREGATE=1300 TO 1500KG/M3